\[\genfrac{(}{)}{0.0pt}{}{z}{0}-\genfrac{(}{)}{0.0pt}{}{z}{1}+\dots+(-1)^{m}%
\genfrac{(}{)}{0.0pt}{}{z}{m}=(-1)^{m}\genfrac{(}{)}{0.0pt}{}{z-1}{m}.\]