\[F\left({-m,b\atop c};z\right)=\frac{{\left(b\right)_{m}}}{{\left(c\right)_{m}}%
}(-z)^{m}F\left({-m,1-c-m\atop 1-b-m};\frac{1}{z}\right)=\frac{{\left(b\right)%
_{m}}}{{\left(c\right)_{m}}}(1-z)^{m}F\left({-m,c-b\atop 1-b-m};\frac{1}{1-z}%
\right),\]